(27)^2x+1=1/3

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Solution for (27)^2x+1=1/3 equation: 



(27)^2x+1=1/3

We move all terms to the left:

(27)^2x+1-(1/3)=0

We add all the numbers together, and all the variables

27^2x+1-(+1/3)=0

We get rid of parentheses

27^2x+1-1/3=0

We multiply all the terms by the denominator


27^2x*3-1+1*3=0

We add all the numbers together, and all the variables

27^2x*3+2=0

Wy multiply elements

81x^2+2=0

a = 81; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·81·2
Δ = -648
Delta is less than zero, so there is no solution for the equation

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